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Suppose

0 Comment

1.94

g

of sodium bromide is dissolved in250.

mL

of

Given that,
Amount of sodium bromide = 1:94 g
Moles of sodium bromide ( NaBr) can be calculated as,
Moles of sodium bromide ( NaBr) = Mass of NaBr
Molar mass of NaBr
Moles of NaBr = 1.94,g
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