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Consider the dissolution of the slightly soluble salt silver chlorite (AgCIO,) with a K, value of 2.0 x 106.
1. Calculate the mass (in grams) that dissolves in 1.00 L of deionized water.
The dissolution reaction of AgCIO, is: AgCIO, (s) — Ag* (aq) + CIO2 (aq)
Since the cation to anion ratio is 1:1, K.,= S’. Based on the K., value, solve for S, then convert it to mass
solubility
S = 120×10- =1.414×10-3 M = 1414 x10-3 mo!
175321 8 – 02479
2. Calculate the mass (in grams) that dissolves in 1.00 L of an aqueous solution buffered at pH = 1.50
Since a pH value is given, you need to calculate K’
For this you will need to look up the Ka value for the conjugate acid of the anion: CIO,
The conjugate acid is HCIO, and its K. value is 1.1 x 102
Ka + [H,07]
K.
= (2.0×10-6 ) (11×10-2 )+(invlog(-150))
(11×10-2)
– 7.75×109
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