(2) A 100.00-mL sample of 0.2000M glycine, A form (see structure below), was titrated with 0.2000M
of NaOH. Kal of glycine = 3.16×10-3; Kaz of glycine = 2.51×10-10
(a) What is the pH after the addition of 100.00 mL of NaOH?
(b) What is the pH after the addition of 180.00 mL of NaOH?Science