1 = 15Xd = 1.4Sd = 2. 4727( 3) Test Statistic: (t – test )to =1.4 – 02-4727t = 1.4= 2.1930. 6385Critical value: ( reject He if )to 2 taivV=n – 1=15 – 1gt; to.05, 19V = 14usingto…Statistics and Probability